Problems on Ages - General QuestionsProblems on Ages - Data Sufficiency 1Problems on Ages - Data Sufficiency 2Problems on Ages - Data Sufficiency 3
11.A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, then how old is B ? A) 7 B) 8 C) 9 D) 10 E) 11 View Answer Report DiscussAnswer: Option DExplanation:Let C's age be x years .Then B's age = 2x years .A's age = (2x+2) years (2x+2)+2x+x=275x = 25x= 5Hence B's age = 2x = 10 years
12.The ratio between the school ages of Neelam and Shaan is 5 : 6 respectively. If the ratio between the one-third age of Neelam and half of Shaan's age is 5 : 9, then what is the school age of Shaan ? A) 25 years B) 30 years C) 36 years D) Cannot be determined E) None of these View Answer Report DiscussAnswer: Option DExplanation:Let the school ages of neelam and Shaan be 5x and 6x years respectivelyThen $\frac{\frac{1}{3}\times5x}{\frac{1}{2}\times6x}= \frac{5}{9}$$=>(\frac{1}{3}\times9\times5x)=(\frac{5}{2}\times6x) => 15=15$Thus Shaan's age cannot be determined
13.The ratio of the ages of a man and his wife is 4 : 3. After 4 years, this ratio will be 9 : 7. If at the time of marriage, the ratio was 5:3, then how many years ago were they married ? A) 8 years B) 10 years C) 12 years D) 15 years View Answer Report DiscussAnswer: Option CExplanation:Let the present ages of the man and his wife be 4x and 3x years repectivelythen , $\frac{4x+4}{3x+4}= \frac{9}{7}$$=>7(4x+4)=9(3x+4)$$=>x =8$So their present ages are 32 years and 24 years respectively .Suppose they were married z years agoThen $\frac{32-z}{24-z}=\frac{5}{3}$$=>3(32-z)=5(24-z)$$=>2z =24$$=> z=12$
14.The present ages of three persons are in proportions 4:7: 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years). A) 8, 20, 28 B) 16. 28. 36 C) 20, 35, 45 D) None of these View Answer Report DiscussAnswer: Option BExplanation:Let their present ages be 4x,7x and 9x years repectively Then (4x-8)+(7x-8)+(9x-8)=56=> 20x = 80=> x= 4Their present ages are 16 years, 28 years and 36 years respectively
15.The ratio of the father's age to his son's age is 7 : 3. The product of their ages is 756. The ratio of their ages after 6 years will be : A) 5 : 2 B) 2:1 C) 11:7 D) 13:9 View Answer Report DiscussAnswer: Option BExplanation:let the present ages of the father and son be 7x and 3x years respectively then $7x\times3x\times=756$$=>21x^{2}=756$$=>x^{2}=36$$=>x=6$ Required ratio = $(7x+6):(3x+6) = 48:24 =2:1$
Problems on Ages - General QuestionsProblems on Ages - Data Sufficiency 1Problems on Ages - Data Sufficiency 2Problems on Ages - Data Sufficiency 3
